Answer:
50 Watt
Explanation:
The question says "A water heater 200 Watt, 220 volts which is installed on a voltage source of 110 volts, absorbs electric power of ?"
The formula for electric power is given by :
[tex]P=\dfrac{V^2}{R}[/tex]
V is voltage and R is resistance
The value of R is same for both the cases.
[tex]R=\dfrac{V^2}{P}[/tex]
or
[tex]\dfrac{V_1^2}{P_1}=\dfrac{V_2^2}{P_2}[/tex]
We have, P₁ = 200 W, V₁ = 220 V, V₂ = 110 V, P₂ = ?
[tex]\dfrac{V_1^2}{P_1}=\dfrac{V_2^2}{P_2}\\\\P_2=\dfrac{P_1V_2^2}{V_1^2}\\\\P_2=\dfrac{200\times 110^2}{220^2}\\\\P_2=50\ W[/tex]
So, the required power is 50 Watt.
