Answer:
Step-by-step explanation:
(a) The length and breadth of the playground as measured by the surveyor are 20 m and 13 m respectively to nearest metre.
Since the actual length is x m and breadth is y m, then;
i. x ≥ 20 m or x ≤ 20 m
ii. y ≥ 13 m or y ≤ 13 m
(b) perimeter of the playground = 2 (length + breadth)
= 2 ( 20 + 13)
= 2 x 33
= 66 m
The range of values of the perimeter = 65.4 m < perimeter < 66.5 m
ii. area of the playground = length x breadth
= 20 x 13
= 260 [tex]m^{2}[/tex]
The range of values of the area = 259.4 [tex]m^{2}[/tex] < Area < 260.5 [tex]m^{2}[/tex]
